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How to Manual: Multi morph and Punnet Squares....
| How to Manual: Multi morph and
Punnet Squares.... I documented this on my BCI work
but will work the same with any species. |
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Often I see where the same
folks that can figure out a simple punnet square on one or
two morphs are struggling to figure out the outcomes when
multiple morph genetics are involved. It's actually fairly
simple and straightforward.
There are two basic outcomes of interest.....
1) What visual phenotypes should/could pop out
2) What are the probabilities of any of those specific
outcomes
Both are easily answered with just a little math....
For example Jungle Sunglow het Moonglow x Jungle het Snow
(complicated on purpose)
Expand that out to show all the genetics involved......
Jungle, Hypo, Albino, het Anery x Jungle, het Albino, het
anery
Now separate them into the individual traits, remember to
show both animals for each trait......
Jungle x Jungle
Hypo x Normal
Albino x Het Albino
Het Anery x Het Anery
Then work out the visual phenotypes and odds for each
trait.....
Jungle x Jungle = 1/4 Super Jungle, 1/2 Jungle, 1/4 Normal
Hypo x Normal = 1/2 Hypo, 1/2 Normal
Albino x Het Albino = 1/2 Albino, 1/2 Normal
Het Anery x Het Anery = 1/4 Anery, 3/4 Pos het Anery
The total number of visual phenotypes equals the product of
the individual trait phenotypes (multiply them all
together)....
#Jungle x #Hypo x #Albino x #Anery = 3 x 2 x 2 x 2 = 24
Which says if the litter were large enough and the odds gods
were totally fair, there would be 24 different looks in all
the babies.
To figure out the odds on any one of those outcomes (yeah,
if you want all 24 you have to repeat the process 23 more
times) Pick one phenotype from each of the visual traits.
Then multiply the odds for each of those phenotypes.....
Examples....
Super Jungle, Hypo, Albino, Anery (yeah, might not able to
visually ID all the traits with all that's going on, for the
sake of this discussion, all are visible one way or
another))
1/4 x 1/2 x 1/2 x 1/4
Or 1 x 1 x 1 x 1 over 4 x 2 x 2 x 4 = 1/64 or one in 64
babies from that pairing would be a Super Jungle Moonglow
One more, what are the odds on normal looking wild type baby
(remember, you have to select one from each group) so......
Normal(Jungle) x Normal(Hypo) x Normal(Albino) x
Normal(Anery)
1/4 x 1/2 x 1/2 x 3/4 = 3/64
Hope this helps, I know many get confused at first but once
you grasp the concept, you'll always know how to figure out
even the most complicated outcomes.
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Dave Colling
Email Us
Rainbowsrus@sbcglobal.net
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